Female Nike Uptempo Outfit, At time t = 0 , a student throws a set of keys vertically .. At time t=0, a student throws a set of keys vertically upward to her sorority sister, who is in a window at distance h above. The second student catches the .Questions & answersTopprQuestionA student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00 m above. The second student catches the keys 1.50 s later. (a) With what initial velocity were the keys thrown? (b) What was the velocity of the keys just before they were caught?Answer · 44 votesWe model the keys as a particle under the constant free - fall acceleration. Take the first student’s position to be yi = 0 and the second student’s position to be yf = 4.00 m . We are given that the time of flight of the keys is t = 1.50 s , and ay = - 9.80m/s^2 (a) We choose the equation yf = yi + vyit + 12ayt^2 to connect the data and the unknown.we solve vyi = yf-y_i- 12ayt^2t and substitute, vyf = 4.00m - 12( - 9.80m/s^2)(1.50s)^21.50s = 10.0m/s (b) The velocity at any time t>0 ios given by vyf = vyi + ayt Therefore, at t = 1.50s vyf = 10.0m/s - (9.80m/s^2)(1.50s) = - 4.68m/s The negative sign means that the keys are moving downward just before they are caught.MoreCheggQuestionA student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00m above. The second student catches the keys 1.50s later. (a) With what initial velocity were the keys thrown? (b) what was the velocity of the keys just before they were caught?Answer · 1 voteGiven that, (a) fromMoreStudy.comQuestionA student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00.Answer · 0 votesGiven data:• The distance travelled by keys is s=4.00m.• The time taken by keys during its travel is t=1.50s.(a)The expression for the initial velocity of the keys thrown is given as,s=ut+12gt2Here, g is the acceleration due to gravity and its standard value is 9.81m/s2.Substitute values in the above expression.4.00m=(u×1.50s)+[12×(−9.81m/s2)×(1.50s)2]u=10m/sThus, the initial velocity of the keys thrown is 10m/s.(b)The expression for the velocity of the keys just before they caught is given as,v=u+gtSubstitute values in the above expression.v=10m/s+(−9.81m/s2×1.50s)v=−4.68m/sHere, -ve sign indicates that the direction of keys are downward.Thus, the velocity of the keys just before they caught is 4.68m/s.MoreStudocuQuestionA student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00 m above. The keys are caught 1.50 s later by the sister’s outstretched hand. (a) With what initial velocity were the keys thrown? (b) What was the velocity of the keys just before they were caught?Answer · 0 votesa) Apply the second kinematic equation along the vertical motion and substitute the required values to determine the value of the initial velocity. h = u t - 1 2 g t 2 4 m = u 1 . 50 s - 1 2 9 . 81 m/s 2 1 . 50 s 2 u = 10 . 024 m/s u ≈ 10 m/s -- b) Apply the first kinematic equation along the vertical motion and substitute the required values to determine the value of the final velocity. v = u - g t v = 10 m/s - 9 . 81 m/s 2 1 . 5 s v = - 4 . 715 m/s Here, the negative sign indicates that the set of keys is moving downward before they are caught.MoreQuoraQuestionA student throws a set of keys vertically upward to her sorority sister, who is in a window 4 m above. The keys are caught 1.5 s later by the sister’s outstretched hand. (a) With what initial velocity were the keys thrown?Answer · 2 votesA student throws a set of keys vertically upward to her sorority sister, who is in a window 4 m above. The keys are caught 1.5 s later by the sister’s outstretched hand. (a) With what initial velocity were the keys thrown?MoreBartleby.comQuestiona student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00m above. the second student catches the keys 1.50 s later.with what initial velocity were the keys thrown? what was the velocity of the keys just before they were caught?Answer · 0 votesStep 1 .MorePearsonQuestionA student throws a set of keys vertically upward to her sorority .Answer · 6 votes(a) v0y=16.7 m/s(b) vy=2 m/sMoreStudy.comQuestionA student throws a set of keys vertically upward to his fraternity brother, who is in a window.Answer · 0 votesGiven:• Height y=4 m• Time t=1.5 sPart A:The initial velocity of the keys isy=yi+vit−12gt24 m=0+vi(1.5 s)−12(9.8 m/s2)(1.5 s)2vi=10.02 m/sPart B:The velocity of the keys just before they were caught isvf=vi−gtvf=10.02 m/s−(9.8 m/s2)(1.5 s)vf=−4.68 m/sNegative sign means the keys are moving downward.MoreBrainlyQuestion4. A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00 m above. The second student catches the keys 1.50 s later. (a) With what initial velocity were the keys thrown? (b) What was the velocity of the keys just before they were caught?​Answer · 3 votesAnswer: a) 10.0 m/s b) -4.68 m/s Explanation: Given: y₀ = 0 m y = 4.00 m t = 1.50 s a = -9.8 m/s² Find: v₀, v y = y₀ + v₀ t + ½ at² 4.00 = 0 + v₀ (1.50) + ½ (-9.8) (1.50)² v₀ = 10.0 m/s v = at + v₀ v = (-9.8) (1.50) + 10.0 v = -4.68 m/sMoreBrainlyQuestionA student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. The brother’s outstretched hand catches the keys 1.50 s later. (a) With what initial velocity were the keys thrown? (b)What was the velocity of the keys just before they were caught?Answer · 0 votesAnswer:10.02 m/s4.68 m/sExplanation:Givenheight of building=4 mtime taken=1.5 s(a)Let u be the initial velocity using equation of motion[tex]s=ut+frac{gt^2}{2}[/tex][tex]4=utimes 1.5-frac{9.81times 1.5^2}{2}[/tex][tex]8=utimes 3-9.81times 2.25[/tex]u=10.02 m/s(b)Velocity of keys just before keys were caught[tex]v^2-u^2=2as[/tex][tex]v^2=10.02^2-2(-9.81)cdot 4[/tex][tex]v^2=21.92[/tex][tex]v=sqrt{21.92}=4.68 m/s[/tex]MoreQuizletQuestionA student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. The brother’s outstretched hand catches the keys 1.50 s later. With what initial velocity were the keys thrown?Answer · 0 votesHere the height of the window where hand catches the keys $S = 4.00,mathrm{m}$.The time period between throw and catch $t = = 1.50,mathrm{s}$.Here the motion of the keys is only under gravitational force so the acceleration $a = -,g = -,9.8,mathrm{m,s^{-1}}$.$textbf{(a)}$ Now as we know from the kinematic equation$$begin{align*}S = v_{text{i}},t + frac{1}{2},a,t^2tag{1}end{align*}$$By rearranging the above equation, we get$$begin{align*}v_{text{i}} & = frac{2,S - ,a,t^2}{2,t}& = frac{2,times 4.00,mathrm{m} - ,left(-,9.8,mathrm{m,s^{-1}}ight),times left(1.50,mathrm{s}ight)^2}{2,times 1.50,mathrm{s}}& = 10.0,mathrm{m,s^{-1}}end{align*}$$ $textbf{(a)}$ $v_{text{i}} = 10.0,mathrm{m,s^{-1}}$MoreCourse HeroQuestionAt time t=0, a student throws a set of keys vertically upward to her sorority sister, who is in a window at distance h above. The second student catches the keys at time t.(a) With what initial velocity were the keys thrown?Answer · 0 votesvi = (h+4.9t2)/tMoreDoubtnutQuestion(a) A student throws a ball vertically upward so tha it just reaches the height of window on th second floor of a dormitory. At the same time the ball is thrown upward, a student at the windoe drops a ball. Are the mechanical energies of the ball the same at half the height of the window ? Exaplain (b) What does work- energy theorem state ?Answer · 1058 votes(a) Yes. When the thrown-up ball is at maximum height, its velocity is zero so it has same energy as the dropped ball. Since the total energy of each ball is conserved, both the balls will have same mechanical energy at half the height of the window. As a matter of fact, both the balls will have the same kinetic and potential energy at half height position. (b) Work done = change in KE (or PE)More Feedback Web results Inspirational Throw Pillow, A student throws a set of keys vertically upward to her .. Thus, the velocity of the keys just before they caught is 4.68 m / s . Help improve Study.com. Report an Error.1 answer  ·  Top answer: Given data:• The distance travelled by keys is s=4.00m.• The time taken by keys during its travel is t=1.50s.(a)The expression for the . Joss And Main Throw Pillows, A student throws a set of keys vertically upward to her sorority. A student throws a set of keys vertically upward to her sorority sister who is in a window 14.00 m above. The second student catches the keys 1.50 s later.3 answers  ·  Top answer: (a) v0y=16.7 m/s(b) vy=2 m/s Kirklands Fall Throw Pillows, Answered: a student throws a set of keys…. SciencePhysicsa student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00m above. the second student catches the keys .1 answer  ·  Top answer: Step 1 . 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